tolong bantu tiga² nya kk,, ini tentang teorema pythagoras... jangan ngasal dan jangan salah ya kk,, makasi banyak
AO = 10 cm
BC = 12 cm
misal : a = tinggi AoD
[tex]a = \sqrt{ {10}^{2} - {6}^{2} } \\ a = \sqrt{100 - 36} \\ a = \sqrt{64} \: \: \: \: \: \: \: \: \: \: \: \\ a = 8 \: cm \: \: \: \: \: \: \: \: \: \: [/tex]
AB = 8 + 8 = 16 cm
[tex]AC = \sqrt{ {16}^{2} + {12}^{2} } \\ AC = \sqrt{256 + 144} \\ AC = \sqrt{400} \: \: \: \: \: \: \: \: \: \: \: \\ AC = 20 \: cm \: \: \: \: \: \: \: \: \: \: [/tex]
K = AB + BC + CD + DA
K = 16 + 12 + 16 + 12
K = 56 cm
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